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Question 2. (i) For Which Values of a and B Does the Following P Exercise 3.5 Chapter 3 Pair of Linear Equations in

Question 2. (i) For which values of a and b does the following pair of linear equations Chapter 3: Pair of Linear Equations in Two Variable Maths Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 2. (i) For which values of a and b does the following pair of linear equations have an infinite number of solutions? 2x +3y =7; (a – b) x +(a +b) y =3a +b –2 is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 3 absolutely free. NCERT Solutions for class 10 Maths Chapter 3: Pair of Linear Equations in Two Variable is very essencial for getting good marks in CBSE Board examinations

Question 2. (i) For which values of a and b does the following pair of linear equations have an infinite number of solutions?
2x +3y =7; (a – b) x +(a +b) y =3a +b –2

Solution: 2x +3y =7
Subtract 7 both side we get
2x + 3y  - 7 =  0
(a – b) x +(a +b) y =3a +b –2
Subtract 3a + b -2 both side we get
(a – b) x +(a +b) y  - (3a + b – 2) = 0

Compare with

 


Hence answer is a = 5 and b = 1

(ii) For which value of k will the following pair of linear equations have no solution?    
3x +y = 1 ; (2k –1) x + (k –1) y = 2k + 1    
3x +y = 1
Subtract 1 both side we get
3x + y – 1 = 0
(2k –1) x + (k –1) y   = 2k + 1
Subtract 2k +1 both side we get
(2k –1) x + (k –1) y – (2k + 1)= 0
3x+y=1 and
(2k-1)x+(k-1)y=2k+1
They can be rewrite as:
3x + y - 1 = 0 and
(2k-1)x + (k-1)y - (2k+1) = 0 
 Compare with

We get  
And for no solution

Take

Cross multiply we get
3k - 3 = 2k - 1
k = 3-1
k = 2
Hence Answer is k = 2

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